How do you calculate # (8.887 times 10^1) /( 9.1 times 10^-2)#?

Answer 1

To calculate (8.887 × 10^1) / (9.1 × 10^-2), you first divide the numerical values: 8.887 ÷ 9.1 = 0.975824. Then, you subtract the exponent in the denominator from the exponent in the numerator: 1 - (-2) = 3. So, the final answer is 0.975824 × 10^3 or 975.824.

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Answer 2

Avery Alexander

Scientific: #8.887/9.1xx10^3# as an exact value

Divided and rounded as scientific
#0.9766xx10^3->9.766xx10^2# to 3 decimal places

Given:# (8.887xx10^1)/(9.1xx10^(-2))#

Note that #10^1 = 10#

We also have #1/10^(-2)# This means that the ten is moved to the numerator giving: #1/(10^(-2))=10^2#

Write as: #(8.887xx10xx10^2)/9.1#

#8.887/9.1xx10^3#

It is customary to use the same format as the question unless specifically instructed otherwise. The question does not specify whether the answer must be in decimal or scientific form.

I suspect that #8.887-:9.1# is an irrational number in that the decimal never stops. So a decimal solution would have to be rounded. Whereas #(8.887xx10^3)/9.1# is an exact value

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.