How do you balance this equation: #?NaHCO_3 → ?NaOH + ?CO_2#?

Answer 1

All question marks get 1.

#NaHCO_3 -> NaOH + CO_2#

Verify it if you compute reactants and products:

Reactants: #1 Na, 1 H, 1 C, and 3 O# Products: #1 Na, 1 H, C, and (1+2) O#

This response is in equilibrium:

#NaHCO_3 -> NaOH + CO_2#
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Answer 2

It is already balanced.

O is oxygen, C is carbon, H is hydrogen, and Na is sodium.

Sodium is balanced, there's 1 on each side. Oxygen is also balanced, there's 3 on each side. (For the RHS, add up the O in #NaOH# and #CO_2#. Hydrogen is balanced, there's 1 on each side. Carbon is balanced, there's 1 on each side.
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Answer 3

To balance the equation NaHCO3 → NaOH + CO2, you need to put a coefficient of 1 in front of NaOH and CO2, and a coefficient of 1 in front of NaHCO3. So, the balanced equation is:

1NaHCO3 → 1NaOH + 1CO2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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