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How do you balance these equations: #?Be(OH)_2 -> ?BeO + ?H_2O# and #?MnS + ?HCl -> ?H_2S + ?MnCl_2#?

Answer 1

Wyatt Adkins

#Be(OH)_2(s) + Delta rarr BeO(s) + H_2O(g)#

Additionally.

#MnS(s) + 2HCl(aq) rarr MnCl_2(aq) + H_2S(aq)#

Are the mass and charge components of these equations balanced?

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Answer 2

Noah Aldrich

To balance the first equation:

Be(OH)₂ -> BeO + H₂O

You need to add a coefficient of 1 in front of BeO and 2 in front of H₂O:

Be(OH)₂ -> BeO + 2H₂O

To balance the second equation:

MnS + HCl -> H₂S + MnCl₂

You need to add coefficients of 2 in front of HCl and MnCl₂:

MnS + 2HCl -> H₂S + MnCl₂

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you balance these equations: #?Be(OH)_2 -&gt; ?BeO + ?H_2O# and #?MnS + ?HCl -&gt; ?H_2S + ?MnCl_2#?

How do you balance these equations: #?Be(OH)_2 -> ?BeO + ?H_2O# and #?MnS + ?HCl -> ?H_2S + ?MnCl_2#?