How do you balance #Si(OH)_4 + NaBr - SiBr_4 + NaOH#?

Question

How do you balance #Si(OH)_4 + NaBr -> SiBr_4 + NaOH#?

Serenity Allen · Accepted Answer

#"Si(OH)"_4+color(red)4"NaBr"##rarr##"SiBr"_4+color(blue)(4)"NaOH"#

The word equation is now, "One mole silicon tetrahydroxide plus four moles sodium bromide produce one mole silicon tetrabromide plus four moles sodium hydroxide."

Inelastic Equation #"Si(OH)"_4+"NaBr"##rarr##"SiBr"_4+"NaOH"# The reaction can be described by the following word equation: "Silicon tetrahydroxide plus sodium bromide produce silicon tetrabromide plus sodium hydroxide." To find the solution to a chemical equation, we count the atoms (or moles) of each element on both sides of the equation and add coefficients in front of each formula if the numbers of each element differ. Bringing the Equation into Balance Think of #"OH"#, as a single species. There are 4 #"OH"# on the left and 1 on the right. To balance them, place a coefficient of #color(blue)4# in front of NaOH. #"Si(OH)"_4+"NaBr"##rarr##"SiBr"_4+color(blue)(4)"NaOH"# The #"OH"# is now balanced with 4 on each side. There are now 4 #"Na"# atoms on the right side and 1 on the left. To balance them, place a coefficient of #color(red)4# in front of NaBr. #"Si(OH)"_4+color(red)4"NaBr"##rarr##"SiBr"_4+color(blue)(4)"NaOH"# There are now 4 sodium atoms on both sides, and there are also now 4 bromine atoms, #"Br"#, on both sides. With the same number of atoms (or moles) of each element on both sides—1 Si, 4 O, 4 H, 4 Na, and 4 Br—the equation is now perfectly balanced. Observe that I added coefficients to alter the quantity of the species involved in the reaction, but I did not alter the subscripts.

Serenity Allen · Answer

undefined The balanced chemical equation for the reaction is: Si(OH)4 + 4NaBr -> SiBr4 + 4NaOH.

How do you balance #Si(OH)_4 + NaBr -&gt; SiBr_4 + NaOH#?

How do you balance #Si(OH)_4 + NaBr -> SiBr_4 + NaOH#?