How do you balance redox reactions in basic solution?
This is a lengthy response, so be warned: in basic solution, redox equations are balanced as though they were in acid, and OH⁻ is used to convert to base at the end.
AN EXAMPLE
In basic solution, balance the following equation: MnO₄⁻ + CN⁻ → MnO₂ + CNO⁻
Resolution:
Divide the equation into two half-reactions, as follows: MnO₄⁻ → MnO₂ CN⁻ → CNO⁻.
Step 2: Align every atom except for H and O. Completed
Step3: Add H₂O to the deficient side to balance O. MnO₄⁻ → MnO₂+ 2H₂O CN⁻+ H₂O → CNO⁻
In step four, add H⁺ to the deficient side to balance H. MnO₄⁻+ 4H⁺ → MnO₂+ 2H₂O CN⁻+ H₂O → CNO⁻ + 2H⁺
Step 5: Add electrons to the more positive side to balance the charge. MnO₄⁻+ 4H⁺ + 3e⁻ → MnO₂+ 2H₂O CN⁻+ H₂O → CNO⁻ + 2H⁺ + 2e⁻
Step 6: The first half-reaction is multiplied by two, and the second half-reaction is multiplied by three. This gives the lowest common multiple of the electrons transferred, which in this case is six.
3 × [CN⁻+ H₂O → CNO⁻ + 2H⁺ + 2e⁻] 2 × [MnO₄⁻+ 4H⁺ + 3e⁻ → MnO₂+ 2H₂O]
Step 7: Combine the two half-reactions, eliminating terms that are similar.
3CN + 2H + 2MnO₄⁻ → 2MnO₂ + 3CNO⁻ + H₂O
This is the acid solution's balanced equation, which we now need to convert to the base solution.
Step 8: In order to cancel the H in the redox equation and cancel like terms, add enough multiples of the equations H⁺ + OH⁻ → H₂O or H₂O → H⁺ + OH⁻.
2MnO₄⁻+ 3CN⁻+ 2H⁺ → 2MnO₂ + 3CNO⁻ + H₂O 2H₂O → 2H⁺ + 2OH⁻
3CN + H₂O + 2MnO₄⁻ → 2MnO₂ + 3CNO⁻ + 2OH⁻
Step 9: Verify that the atoms are in balance. The following are listed from left to right: 2 Mn, 9 O, 3 C, 3 N, and 2 H.
Step 10: Verify the charges balance. 2- + 3- = 5- On the left; 3- + 2- = 5- On the right.
Equation 2MnO₄⁻+ 3CN⁻+ H₂O → 2MnO₂ + 3CNO⁻ + 2OH⁻ is balanced.
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- Identify the oxidation and reduction half-reactions.
- Balance the elements in each half-reaction, excluding oxygen and hydrogen.
- Balance oxygen atoms by adding water molecules to the side lacking oxygen.
- Balance hydrogen atoms by adding hydrogen ions to the side lacking hydrogen.
- Balance charge by adding electrons to the side with a higher positive charge.
- Multiply each half-reaction to ensure the electrons cancel out.
- Add the balanced half-reactions, canceling out common terms.
- Check that mass and charge are balanced.
- If in a basic solution, add hydroxide ions to both sides to neutralize hydrogen ions, then simplify the equation.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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