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How do you balance #P_4 + Br_2 -> PBr_3#?

Answer 1

We must make sure the number of molecules in each element on each side of the equation are equal.

The lowest number of #P_4# that we can have is #1P_4#, which means one molecule of 4 atoms of phosphorus.

Therefore, we need four P atoms on the other side. To calculate this, we create the following equation:

#1P_4 + Br_2 -> 4PBr_3#

This means that we have (#4 xx 3 = 12)# atoms of bromine. To finish the balancing process, we need to balance the bromine on the other side of the equation. It would be #6br_2# to make 12 atoms of bromine.

So, your equation will be #P_4 + 6Br_2 -> 4PBr_3#

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Answer 2

Wyatt Atkins

The balanced chemical equation for the reaction ( P_4 + Br_2 \rightarrow PBr_3 ) is:

[ P_4 + 6Br_2 \rightarrow 4PBr_3 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you balance #P_4 + Br_2 -&gt; PBr_3#?

How do you balance #P_4 + Br_2 -> PBr_3#?