How do you balance #LiAl(OH)_4 + H_2O - LiOH + Al(OH)_3 + H_2O#?

Question

How do you balance #LiAl(OH)_4 + H_2O -> LiOH + Al(OH)_3 + H_2O#?

Serenity Allen · Accepted Answer

Since it's already balanced, let's check what's on each side to see what happens. #"LiAl"("OH")_4 + cancel("H"_2"O") -> "LiOH" + "Al"("OH")_3 + cancel("H"_2"O")# #color(green)("Li")color(highlight)("Al")color(blue)(("OH")_4) -> color(green)("Li")color(blue)("OH") + color(highlight)("Al")color(blue)(("OH")_3)# Yep, it's fine the way it is. One lithium on each side, one aluminum on each side, and four #"OH"# groups on each side.  As for the charges, #"Al"("OH")_4^(-)# is balanced by #"Li"^(+)#, #"OH"^(-)# is balanced by #"Li"^(+)#, and #3xx"OH"^(-)# is balanced by #"Al"^(3+)#.

Jeremiah Adams · Answer

Do you mean the reaction of lithium tetrahydroaluminate (#LiAlH_4#) with water?

#LiAlH_4(s) + 4H_2O(l) rarr LiAl(OH)_4(aq) + 4H_2(g)uarr# Lithium tetrahydroaluminate is an important hydride transfer reagent, and a very common reductant in organic chemistry. The reduction reaction is performed in THF (#C_4H_8O#) or ether (both solvent must be dry). #LiAlH_4# can transfer up to 4 hydrides (with commercial grades usually it transfers about 3). When your organic reduction is finished, the mixture is worked up with water. This can get pretty violent (especially if the lithal has been added 1:1, as is quite commonly done).

Cooper Anderson · Answer

undefined To balance the chemical equation LiAl(OH)4 + H2O -> LiOH + Al(OH)3 + H2O, you would need to adjust the coefficients of the compounds to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is:

LiAl(OH)4 + H2O -> LiOH + Al(OH)3 + H2O

How do you balance #LiAl(OH)_4 + H_2O -&gt; LiOH + Al(OH)_3 + H_2O#?

How do you balance #LiAl(OH)_4 + H_2O -> LiOH + Al(OH)_3 + H_2O#?