How do you balance #FeO + PdF_2 -> FeF_2 + PdO#?

I assume this is a high-temperature solid state reaction; whether the reaction makes sense is another story.

Balanced equation: 3FeO + 2PdF₂ -> 3FeF₂ + 2PdO.

To balance the chemical equation FeO + PdF2 -> FeF2 + PdO, you need to ensure that the number of atoms of each element is the same on both sides of the equation.

Here's the balanced equation:

FeO + PdF2 -> FeF2 + PdO

To balance the equation, we can follow these steps:

1. Count the number of atoms for each element on both sides of the equation.
2. Start by balancing the atoms that appear only once on each side.
3. Balance the remaining atoms, ensuring that the same number of each type of atom appears on both sides of the equation.

Balancing the equation:

FeO + PdF2 -> FeF2 + PdO

Fe: 1 on the left, 1 on the right Pd: 1 on the left, 1 on the right O: 1 + 2 = 3 on the left, 2 + 1 = 3 on the right F: 2 on the left, 2 on the right

To balance the oxygen atoms, we can add a coefficient of 2 in front of FeO and PdO:

2FeO + PdF2 -> FeF2 + 2PdO

Now, let's check if the equation is balanced:

Fe: 2 on the left, 1 on the right Pd: 1 on the left, 2 on the right O: 21 + 21 = 4 on the left, 12 + 21 = 4 on the right F: 2 on the left, 2 on the right

All the atoms are balanced, and the equation is now balanced.