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How do you balance #Fe+H_2SO_4 -> Fe_2(SO_4)_3 + H_2#?

Answer 1

#2Fe_((s)) + 3H_2SO_(4(aq)) -> Fe_2(SO_4)_(3(aq)) +# #3H_2#(g)

Start by looking at the most complex compound, and balancing around that. In this case, its #Fe_2(SO_4)_(3(aq))#.

We see that we need 2 Fe and 3 #SO_4# on the reactants side, so we add those in. After that, there is only an imbalance of #H_2#, which is easily fixed by adding a 3 to the products side.

Since it is much more difficult to try to balance the more complex compound to the rest of the equation, the general method of balancing is to start with the most complex compound first and make sure the rest of the equation follows suit.

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Answer 2

Olivia Anton

To balance the equation Fe + H₂SO₄ → Fe₂(SO₄)₃ + H₂, you need to multiply Fe by 3, H₂SO₄ by 3, and H₂ by 3. The balanced equation is: 3Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you balance #Fe+H_2SO_4 -&gt; Fe_2(SO_4)_3 + H_2#?

How do you balance #Fe+H_2SO_4 -> Fe_2(SO_4)_3 + H_2#?