How do you balance #C_5H_5 + Fe→ Fe(C_5H_5)_2#?

Answer 1

Well, you do that by having two #"C"_5"H"_5# molecules:

#2"C"_5"H"_5 + "Fe" -> "Fe"("C"_5"H"_5)_2#

But I don't think a neutral #"C"_5"H"_5# exists or is readily found. I would have done it the following way instead. This is actually a rather interesting reaction:

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Answer 2

To balance the equation ( \text{C}_5\text{H}_5 + \text{Fe} \rightarrow \text{Fe(C}_5\text{H}_5\text{)}_2 ), you need to add a coefficient to each compound to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is:

[ \text{C}_5\text{H}_5 + 2\text{Fe} \rightarrow \text{Fe(C}_5\text{H}_5\text{)}_2 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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