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How do you balance #AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3#?

Answer 1

#2AlBr_3 + 3K_2SO_4 rarr 6KBr + Al_2(SO_4)_3#

All you need to do to balance this equation is to ensure that the reactant and product sides have the same amount of each element.

Gradually balancing:

#AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactionants: Al - 1 Br - 3 K - 2 S - 1 O - 4 products: Al - 2 Br - 1 K - 1 S - 3 O - 12

#AlBr_3 + 3K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactants: Al - 1 Br - 3 K - 6 S - 3 O - 12 products: Al - 2 Br - 1 K - 1 S - 3 O - 12

#2AlBr_3 + 3K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

Al - 2 Br - 6 K - 6 S - 3 O - 12 reactants and products are Al - 2 Br - 1 K - 1 S - 3 O - 12.

#2AlBr_3 + 3K_2SO_4 -> 6KBr + Al_2(SO_4)_3# (balanced)

reactants: Al - 2 Br - 6 K - 6 S - 3 O - 12 products: Alpha - 2 Br - 6 K - 6 S - 3 O - 12

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Answer 2

Peyton Adams

The balanced chemical equation for the reaction AlBr3 + K2SO4 -> KBr + Al2(SO4)3 is:

2AlBr3 + 3K2SO4 -> 6KBr + Al2(SO4)3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you balance #AlBr_3 + K_2SO_4 -&gt; KBr + Al_2(SO_4)_3#?

How do you balance #AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3#?