How do you balance #AgNO_3 +MgCl_2 → AgCl + Mg(NO_3)_2#?

Question

Peyton Adams · Accepted Answer

#2"AgNO"_3 +"MgC"l_2 → 2"AgC"l + "Mg(NO"_3")"_2# On the RHS, we have two nitrate ions. Therefore, we need #2# mols of #"AgNO"_3# to balance them. We now have two mols of #"Ag"^+# on the LHS but only one mol on the RHS. Thus we also need #2# mols #"AgC"l#.

Kai Bowman · Answer

undefined 2AgNO₃ + MgCl₂ → 2AgCl + Mg(NO₃)₂

Mateo Aguilar · Answer

undefined To balance the chemical equation $ \text{AgNO}_3 + \text{MgCl}_2 \rightarrow \text{AgCl} + \text{Mg(NO}_3)_2 $, follow these steps:

1. Count the number of atoms of each element on both sides of the equation.

2. Start by balancing the elements that appear only once on each side of the equation. In this case, it's Ag and Mg.

3. Balance Ag atoms:
   There is 1 Ag atom on the left side and 1 Ag atom on the right side, so Ag is already balanced.

4. Balance Mg atoms:
   There is 1 Mg atom on the left side and 1 Mg atom on the right side, so Mg is also already balanced.

5. Now, balance the other atoms: N and O in NO3 and Cl.

6. Balance N atoms:
   There are 1 N atom in AgNO3 and 2 N atoms in Mg(NO3)2, so we need to put a coefficient of 2 in front of AgNO3 to balance N.

7. Balance O atoms:
   There are 3 O atoms in AgNO3 and 6 O atoms in Mg(NO3)2, so the coefficients in front of AgNO3 and Mg(NO3)2 should be adjusted accordingly. We already have 2 AgNO3, so we need to put a coefficient of 3 in front of Mg(NO3)2.

8. Now, balance Cl atoms:
   There are 2 Cl atoms in MgCl2 and 1 Cl atom in AgCl. To balance Cl, we need to put a coefficient of 2 in front of AgCl.

The balanced equation is: $ 2\text{AgNO}_3 + \text{MgCl}_2 \rightarrow 2\text{AgCl} + \text{Mg(NO}_3)_2 $.