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How do you add or subtract #(4x+y)/(2x+3y)-(2x-2y)/(2x+3y)#?

Answer 1

Avery Alexander

#(4x+y)/(2x+3y)-(2x-2y)/(2x+3y)#

here the denominator is same so we can rewrite the expression as: #((4x+y)-(2x-2y))/(2x+3y)#

# = (4x+y- 2x +2y)/(2x+3y)# # =cancel (2x +3y)/cancel(2x+3y)# # =1#

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Answer 2

Kennedy Adams

To add or subtract the given expression, (4x+y)/(2x+3y)-(2x-2y)/(2x+3y), we can combine the two fractions since they have the same denominator.

The numerator of the first fraction, (4x+y), remains the same, while the numerator of the second fraction, (2x-2y), changes to its opposite, -(2x-2y), when subtracting.

Combining the fractions, we have (4x+y - (2x-2y))/(2x+3y).

Simplifying the numerator, we get (4x+y - 2x + 2y)/(2x+3y).

Combining like terms in the numerator, we have (2x + 3y)/(2x+3y).

Since the numerator and denominator are the same, the expression simplifies to 1.

Therefore, the result of (4x+y)/(2x+3y)-(2x-2y)/(2x+3y) is 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.