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How do you add #(6x^2-x-4) + (2x^2-x-5)#?

Answer 1

Avery Alexander

#8x^2-2x-9#

The parenthesis are really unnecessary in this problem. We just need to combine our like terms:

The #x^2# terms with each other, the #x# terms with each other, and the constants. Doing this, we get:

#8x^2-2x-9#

The key realization when we're doing problems like these is to see if we have like terms, and if we do, combine them.

Hope this helps!

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Answer 2

Savannah Anderson

To add the expressions (6x^2-x-4) and (2x^2-x-5), you combine like terms: 6x^2 + 2x^2 = 8x^2, -x - x = -2x, and -4 - 5 = -9. So the sum is 8x^2 - 2x - 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.