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How do you add #3/(2x-4)+x/(x+2)#?

Answer 1

#3/(2x-4)+x/(x+2)=(x²-1/2x+3)/(x²-4)#

#3/(2x-4)+x/(x+2)# #=(3/2)/(x-2)+x/(x+2)# #=(3/2(x+2)+x(x-2))/(x²-4)# #=(x²+3/2x-2x+3)/(x²-4)# #=(x²-1/2x+3)/(x²-4)# \0/ here's our answer!

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Answer 2

Eli Assouline

To add the fractions 3/(2x-4) and x/(x+2), you need to find a common denominator. The common denominator in this case is (2x-4)(x+2).

To add the fractions, you multiply the numerator of the first fraction (3) by the denominator of the second fraction (x+2), and multiply the numerator of the second fraction (x) by the denominator of the first fraction (2x-4).

Then, you add the two resulting fractions together and simplify if possible.

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Answer 3

Abigail Allen

To add the expressions 3/(2x-4) and x/(x+2), first find a common denominator, which is (2x - 4)(x + 2). Then rewrite each fraction with this common denominator. After that, combine the numerators over the common denominator. Simplify the resulting expression if necessary.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.