How do we find the zeros from #y=-4(x-3)^2+16# vertex form equation?
Kennedy AdamsAfter x1 - 3 = 2, x1 = 5.
3 - 2.. -> x2 = 1
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Nathan AxelTo find the zeros of the quadratic function in vertex form ( y = -4(x - 3)^2 + 16 ), set ( y ) to zero and solve for ( x ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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