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How do to you write in standard form of a line through point (-3,2) and m=1?

Answer 1

Eva Adamson

The equation in standard form is #x-y=-5#.

Start by writing the equation in point-slope form.

#(y-y_1)=m(x-x_1)# =

#(y-2)=(1)(x-(-3))# =

#y-2=x+3#

Convert to slope-intercept form: #y=mx+b#. Solve for #y#.

#y=x+5#

Convert to standard form: Ax+By=C .

#-x+y=5#

Multiply both sides times -1.

#x-y=-5#

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Answer 2

Jace Anderson

To write the equation of a line in standard form, you need to use the point-slope form of a linear equation, which is (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the point ((-3,2)) and the slope (m = 1), you can substitute these values into the point-slope form and then rearrange the equation to standard form, which is (Ax + By = C). Here's how:

Point-slope form: (y - 2 = 1(x - (-3))) (y - 2 = x + 3)

Rearranging to standard form: (y - x = 3 - 2) (y - x = 1)

To eliminate the negative coefficient of (x), you can multiply both sides of the equation by -1:

(-y + x = -1)

So, the equation of the line in standard form through the point ((-3,2)) with a slope of (m = 1) is (-y + x = -1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.