How do solve the following linear system?: # x+2y =2 , x-2y = -3 #?

Answer 1

Step by step:

First, we need to isolate one variable. The easiest, in this case, is x. #x + 2y =2# becomes #x = 2 -2y#. We now have X's value and need to find Y's value. Second, we change X in the second equation to its new value: #x - 2y=-3# becomes #2 -2y -2y = -3#. Solving the new equation: #2 - 4y = -3#, then we pass the 2 to the other side of the equation: #-4y = -3 - 2 = -5# and #-4y = -5#, so #y = (-5)/(-4) = 5/4#. With the exact value of Y, we now go back to the first equation: #x = 2 - 2y = 2 - 10/4 = 8/4 - 10/4 = -2/4 ", so, " x = -2/4 " or " -0,5#
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Answer 2

To solve the linear system (x + 2y = 2) and (x - 2y = -3), you can use the method of substitution or elimination.

  1. Using substitution, solve one equation for (x) or (y) and substitute the expression into the other equation to solve for the remaining variable.
  2. Using elimination, add or subtract the equations to eliminate one variable, then solve for the remaining variable.

After finding the values of (x) and (y), verify the solution by substituting them into both equations to ensure they satisfy both equations simultaneously.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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