# How do solve the following linear system?: # 9 x-6y =3 , x + y= 12 #?

Open the brackets and simplify. The product of two negatives is a positive.

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To solve the linear system:

- Start by solving one of the equations for one variable in terms of the other.
- Substitute the expression found in step 1 into the other equation.
- Solve the resulting equation for the variable.
- Once you have the value of one variable, substitute it back into one of the original equations and solve for the other variable.
- Verify the solution by substituting the values of both variables into both original equations.

Given the system:

[9x - 6y = 3] [x + y = 12]

Let's solve equation 2 for (x):

[x = 12 - y]

Now, substitute this expression for (x) into equation 1:

[9(12 - y) - 6y = 3]

[108 - 9y - 6y = 3]

[108 - 15y = 3]

[15y = 105]

[y = 7]

Now, substitute (y = 7) into equation 2 to solve for (x):

[x = 12 - 7]

[x = 5]

So, the solution to the system is (x = 5) and (y = 7).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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