# How do solve the following linear system?: # -6x+5y=1 , 6x+4y=-1 #?

Adding both the equations:

Given that,

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To solve the linear system: -6x + 5y = 1 6x + 4y = -1

You can use the method of elimination or substitution.

Using elimination:

- Multiply the first equation by 6 and the second equation by -6 to eliminate the variable x. -36x + 30y = 6 -36x - 24y = 6
- Add the equations together to eliminate x: (30y - 24y) = 6 + (-1) 6y = 5
- Solve for y: y = 5/6

Using substitution:

- Solve one equation for one variable, say the first equation for x: -6x = -5y + 1 x = (5y - 1)/6
- Substitute this expression for x into the second equation: 6((5y - 1)/6) + 4y = -1
- Solve for y: 5y - 1 + 4y = -1 9y - 1 = -1 9y = 0 y = 0
- Substitute the value of y back into one of the original equations to solve for x: -6x + 5(0) = 1 -6x = 1 x = -1/6

So, the solution to the system is x = -1/6 and y = 5/6.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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