How do I use the vertex formula to determine the vertex of the graph for #y=x^2+4x+1#?

Answer 1
Vertex form of quadratic: #x=m(x-a)^2+b# with vertex #(a,b)#
#y=x^2+4x+1#
#y=(x^2+4x+4) -4 +1#
#y=(x-(-2)) +(-3)#
Vertex is at #(-2,-3)#
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Answer 2

To determine the vertex of the graph for the quadratic function ( y = x^2 + 4x + 1 ), you can use the vertex formula ( x = \frac{-b}{2a} ), where ( a ) is the coefficient of the quadratic term, ( b ) is the coefficient of the linear term, and ( c ) is the constant term. Then, once you have the value of ( x ) from the vertex formula, you can plug it back into the original equation to find the corresponding ( y ) value.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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