How do I use the vertex formula to determine the vertex of the graph for #y=2x^2 + 8x + 5#?
Vertex's x and y coordinates
#y = f[-b/(2a)] = f(-2) = 2.(-2)^2 + 8.(-2) + 5 = = 8 - 16 + 5 = -3#
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To determine the vertex of the graph for (y = 2x^2 + 8x + 5), you can use the vertex formula (x_v = -\frac{b}{2a}), where (a) is the coefficient of (x^2) (in this case, (2)) and (b) is the coefficient of (x) (in this case, (8)). Then, substitute the value of (x_v) into the equation to find the corresponding (y) coordinate.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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