# How do I find the vertex of #y=(x+2)^2-3#?

The vertex is at

The vertex form for the equation of a parabola is

Your equation is already in vertex form

By comparing the two equations, we see that

The vertex is at (

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To find the vertex of the quadratic function ( y = (x + 2)^2 - 3 ), you can identify it directly from the vertex form of a quadratic function, which is ( y = a(x - h)^2 + k ), where (h, k) represents the coordinates of the vertex.

Comparing ( y = (x + 2)^2 - 3 ) with ( y = a(x - h)^2 + k ), we see that ( h = -2 ) and ( k = -3 ). Therefore, the vertex of the function is (-2, -3).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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