How do I find the vertex, axis of symmetry, y-intercept, x-intercept, domain and range of #y=-x^2+2x-5#?
y = -x^2 + 2x - 5
y = -x^2 + 2x - 5 x-coordinate of vertex and axis of symmetry: x = (-b/2a) = -2/-2 = 1 y-coordinate of vertex: y(1) = -1 + 2 - 5 = -4 y-intercept. Make x = 0 --> y = -5 x-intercepts. Make y = 0 -->Solve -x^2 + 2x - 5 = 0. Since D = 4 - 20 < 0, there are no real roots (no x-intercepts) The graph is a parabola that opens downward (a < 0), and that is completely below the x-axis. It has a minimum. (-4) at vertex (1, -4). Domain of x (-infinity, infinity) Range of y (-infinity, -4)and (-4, -infinity) graph{-x^2 + 2x - 5 [-20, 20, -10, 10]}
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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