How do I find the domain of #y=1/x#?
This is a rational function.
The denominator of a rational function cannot be
If the denominator is
If we can find the value(s) that would result in the denominator becoming
This is accomplished by setting the expression in the denominator equal to
In this example the expression,
This means that the only value that the denominator ,
The interval notation for the domain is
By signing up, you agree to our Terms of Service and Privacy Policy
To find the domain of ( y = \frac{1}{x} ), you need to identify the values of ( x ) for which the function is defined. Since division by zero is undefined, the domain of ( y = \frac{1}{x} ) excludes any value of ( x ) that makes the denominator zero. Therefore, the domain of ( y = \frac{1}{x} ) is all real numbers except ( x = 0 ). In interval notation, the domain can be expressed as ( (-\infty, 0) \cup (0, \infty) ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- Let #f(x) = 1/x# and #g(x) = sqrt(x-2)#, how do you find each of the compositions and domain and range?
- How do I find the vertical and horizontal asymptotes of #f(x)=x^2/(x-2)^2#?
- Why do some functions have asymptotes?
- How do you find #f ^-1(x)# given #f(x) = (x+1)/(x+2)# when x ≠ -2?
- What is the inverse function of #y=(3x-4)^2#?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7