# How do you find the limit #lim_(x->2^+)sqrt(2-x)# ?

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To find the limit as x approaches 2 from the right (x->2+), of the function sqrt(2-x), we substitute the value 2 into the function. This gives us sqrt(2-2), which simplifies to sqrt(0). The square root of 0 is 0. Therefore, the limit as x approaches 2 from the right of sqrt(2-x) is 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- What is the limit as x approaches 0 of #sin(3x)/(5x^3-4x)#?
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- When do we know that a limit of a given function exists?

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