# How do find the vertex and axis of symmetry, and intercepts for a quadratic equation #y=x^2-7x-28#?

Find vertex of y = x^2 - 7x - 28

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To find the vertex of a quadratic equation in the form y = ax^2 + bx + c, use the formula x = -b/(2a). Then substitute the x-value into the equation to find the corresponding y-value. The vertex is (x, y).

The axis of symmetry is the vertical line that passes through the vertex. Its equation is x = -b/(2a).

To find the y-intercept, set x = 0 in the equation and solve for y. To find the x-intercepts, set y = 0 in the equation and solve for x using the quadratic formula or factoring.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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