How do find the quotient of #(2x^3 − 3x 2 + x − 6) ÷ (x − 4)#?

How do find the quotient of #(2x^3 − 3x^2 + x − 6) ÷ (x − 4)#?

Answer 1

The quotient polynomial :
#q(x)=2x^2+5x+21 and"the Remainder"=78#

#(2x^3-3x^2+x-6)div(x-4)#

Using synthetic division :

We have , #p(x)=(2x^3-3x^2+x-6) and "divisor : " x=4#
We take ,coefficients of #p(x) to 2,-3,1,-6#
. #4 |# #2color(white)(....)-3color(white)(.......)1color(white)(.......)-6# #ulcolor(white)(...)|# #ul(0color(white)( .........)8color(white)(.......)20color(white)(.........)84# #color(white)(....)2color(white)(........)5color(white)(.......)21color(white)(......)color(violet)(ul|78|# We can see that , quotient polynomial :
#q(x)=2x^2+5x+21 and"the Remainder"=78#

Hence ,

#(2x^3-3x^2+x-6)=(x-4)(2x^2+5x+21 )+(78)#
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Answer 2

To find the quotient of (2x^3 − 3x^2 + x − 6) ÷ (x − 4), you can use long division. Here are the steps:

  1. Divide the first term of the dividend (2x^3) by the first term of the divisor (x). The result is 2x^2.
  2. Multiply the divisor (x − 4) by the quotient obtained in step 1 (2x^2). The result is 2x^3 − 8x^2.
  3. Subtract the result obtained in step 2 from the dividend (2x^3 − 3x^2 + x − 6) to get the new dividend: (-8x^2 + x − 6).
  4. Repeat steps 1-3 with the new dividend (-8x^2 + x − 6).
  5. Divide the first term of the new dividend (-8x^2) by the first term of the divisor (x). The result is -8x.
  6. Multiply the divisor (x − 4) by the quotient obtained in step 5 (-8x). The result is -8x^2 + 32x.
  7. Subtract the result obtained in step 6 from the new dividend (-8x^2 + x − 6) to get the new dividend: (33x − 6).
  8. Repeat steps 5-7 with the new dividend (33x − 6).
  9. Divide the first term of the new dividend (33x) by the first term of the divisor (x). The result is 33.
  10. Multiply the divisor (x − 4) by the quotient obtained in step 9 (33). The result is 33x − 132.
  11. Subtract the result obtained in step 10 from the new dividend (33x − 6) to get the remainder: (126).
  12. The quotient is the sum of the quotients obtained in each step: 2x^2 - 8x + 33.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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