How did the Hooke’s law help IR in the position of absorption bands?

Answer 1

The relevance of Hooke's law is that it is a ball-and-spring model, the basis for the harmonic oscillator, which is the name for the simplified, ideal diatomic that models molecular vibrations.

IR spectroscopy graphs the intensities of molecular vibrations versus their frequencies in wavenumbers (#"cm"^(-1)#), and these frequencies depend on the symmetry and type of vibration. It's not necessary to discuss symmetry to explain the relationship, however. We will only use simple terms, namely "totally symmetric" and "not totally symmetric", to identify what we're talking about.

You may have vibrations (or more formally, "vibrational modes") like the following:

Bends (such as scissoring and rocking) are weaker than stretches (such as symmetric and asymmetric stretching), and the weaker vibrations show up at lower frequencies. You can see so here with methane's vibrational frequencies.

#A_1# symmetry (totally symmetric stretch): #"3025.5 cm"^(-1)#
#E# symmetry (totally symmetric bend): #"1582.7 cm"^(-1)#
#"T"_2"/""F"_2# symmetry (not totally symmetric stretch): #"3156.8 cm"^(-1)#
#"T"_2"/""F"_2# symmetry (not totally symmetric bend): #"1367.4 cm"^(-1)#

You can see that the bends have less motion and therefore imply lesser energetics, and stretches have more motion and imply greater energetics, which visually demonstrates why stretches show up at higher frequencies.

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Answer 2

Hooke's law explains the relationship between the force exerted on an object and its displacement or deformation. In the context of infrared (IR) spectroscopy, Hooke's law helps to determine the position of absorption bands by relating the stretching or bending vibrations of chemical bonds to the masses of the atoms involved and the force constants of those bonds. This relationship allows scientists to predict the frequencies at which molecules will absorb infrared radiation, providing valuable information about their structure and composition.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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