How can you convert this #x^3-x^2-x+1# into #(x-a)(x-b)(x-c)# ?

Is there any formula to convert this #x^3-x^2-x+1# into #(x-a)(x-b)(x-c)#.
If available please help me.

Answer 1

Eva Abramson

#(x-1)(x-1)(x+1)#

Assuming a cubic polynomial

#x^3-x^2-x+1#

#=x^2(x-1)-(x-1)#

#=(x-1)(x^2-1)#

#=(x-1)(x-1)(x+1)#

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Answer 2

Hazel Anglin

#x-1)(x-1)(x+1)#

#"note the sum of the coefficients"#

#1-1-1+1=0#

#"Thus "x=1" is a zero and "(x-1)" is a factor"#

#"dividing "x^3-x^2-x+1" by "(x-1)" gives"#

#(x-1)(x^2-1)#

#=(x-1)(x-1)(x+1)#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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How can you convert this #x^3-x^2-x+1# into #(x-a)(x-b)(x-c)# ?

Is there any formula to convert this #x^3-x^2-x+1# into #(x-a)(x-b)(x-c)#. If available please help me.

Is there any formula to convert this #x^3-x^2-x+1# into #(x-a)(x-b)(x-c)#.
If available please help me.