How can I solve this ? I need to know steps please.. thank you ^^

Answer 1

#y=25# when #x=10#

In a lot of detail!

#color(blue)("Method")#
Determine the value of #k# using #x=8 and y=20#.
With this value for #k# substitute and determine the value of #y# when #x=10# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #color(blue)("Determine the value of "k)#
Let #k# be some constant value (does not change)
The format for; varies directly is #y=kx" "......Equation(1)#
Known condition: at #color(red)(x=8)# the answer of y is #color(green)(y=20)#
Substituting these values into #Equation(1)# we have
#color(green)(y)=kcolor(red)(x)color(white)("ddd")->color(white)("ddd")color(green)(20)=kcolor(red)(8)#

Remove the eighth from the right side of the = by dividing both sides by 8.

#20/8=kxx8/8 larr" Note that "8/8=1#
#20/8=k#
#(20-:4)/(8-:4)=k=5/2#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #color(blue)("Determine "y" when "x=10)#
#y=kxcolor(white)("ddd")->color(white)("ddd")y=5/2x#
Given that #x=10# we have
#color(white)("dddddddd")->color(white)("ddd")y=5/(cancel(2)^1)xxcancel(10)^5#
#color(white)("dddddddd")->color(white)("ddd")y=5xx5=25#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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