# How can I prove that two quadrilaterals are congruent to one another?

Generally, you have to put sides an interior angles of one quadrilateral in correspondence with sides and angle of another and to prove that all corresponding pairs of sides and angles are congruent.

The above follows from the definition of congruence.

Of course, in some specific cases there might be easier solution.

For example, you have compare two rectangles (that is, you you know in advance that both quadrilaterals are rectangles). Then all you have to prove is the congruence of a pair of adjacent sides.

In case of two parallelograms the proper way is to compare a pair of adjacent sides and an angle between them.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- A parallelogram has sides with lengths of #9 # and #8 #. If the parallelogram's area is #56 #, what is the length of its longest diagonal?
- A parallelogram has sides with lengths of #18 # and #5 #. If the parallelogram's area is #42 #, what is the length of its longest diagonal?
- In a parallelogram that is not a rectangle or rhombus, what is the probability of 2 randomly chosen angles being congruent?
- Two rhombuses have sides with lengths of #8 #. If one rhombus has a corner with an angle of #pi/6 # and the other has a corner with an angle of #(pi)/4 #, what is the difference between the areas of the rhombuses?
- What is the difference between a trapezoid and a rhombus?

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