# How can I integrate #sin^2 xcosx#??

Make an appropriate u sub:

By signing up, you agree to our Terms of Service and Privacy Policy

The integral is equal to

Hopefully this helps!

By signing up, you agree to our Terms of Service and Privacy Policy

By signing up, you agree to our Terms of Service and Privacy Policy

Is an inmediate integral. See below

By signing up, you agree to our Terms of Service and Privacy Policy

To integrate ( \sin^2(x)\cos(x) ), you can use the substitution method. Here's how:

- Let ( u = \sin(x) ), then ( du = \cos(x) dx ).
- Rewrite the integral in terms of ( u ): ( \int u^2 du ).
- Integrate ( u^2 ) with respect to ( u ).
- Replace ( u ) with ( \sin(x) ) in the final result.

The integral of ( u^2 ) with respect to ( u ) is ( \frac{1}{3}u^3 + C ), where ( C ) is the constant of integration.

So, the integral of ( \sin^2(x)\cos(x) ) is ( \frac{1}{3}\sin^3(x) + C ), where ( C ) is the constant of integration.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you evaluate the integral #int 1/(x(1+(lnx)^2)#?
- How do you integrate #9sin(ln x) dx#
- How do you integrate #int (x^2-1)/((x)*(x^2+1))# using partial fractions?
- What is #f(x) = int xsqrt(x^2-1) dx# if #f(3) = 0 #?
- How do you use partial fraction decomposition to decompose the fraction to integrate #(x^5 + 1)/(x^6 - x^4)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7