How can I find valence electrons in polyatomic ions?
To determine the number of electrons in polyatomic ions you will need to determine the number of valence electron for each element present in the ion and make a correction given the charge of the ion.
Example 1:
Oxygen has 6 valence electrons
Hydrogen has 1 valence electron
Need 1 more to get the charge of -1
Total number = 8
Example 2:
Nitrogen has 5 valence electrons
Hydrogen has 1 valence electron x 4 (because you have 4 atoms of H)
Need to remove 1 electron to get +1 charge of the ion
Total number = 8
Here are some videos to review to help with this concept.
Video from: Noel Pauller
Video from: Noel Pauller
Hope this helps!
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To find the number of valence electrons in a polyatomic ion, sum the valence electrons of each atom in the ion, then adjust for the ion's charge by adding electrons for each negative charge or subtracting electrons for each positive charge.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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