How can I explain the formula and name of condensed formula #(CH_3)_2C(C_2H_5)_2# according to IUPAC?

Answer 1

First, you recognize that one of the CH₃ groups and one of the C₂H₅ groups is part of the main chain.

Then you can re-write the condensed formula as CH₃-C(CH₃)(C₂H₅)-C₂H₅.

You can expand the right hand C₂H₅ group to get CH₃-C(CH₃)(C₂H₅)-CH₂CH₃.

The structural formula is then

When you number the main chain from the left hand end, the IUPAC name becomes 2-ethyl-2-methylbutane.

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Answer 2

The condensed formula (CH₃)₂C(C₂H₅)₂ can be explained as follows according to IUPAC:

The formula represents a compound with two methyl groups (CH₃) attached to a central carbon atom (C), which is then bonded to two ethyl groups (C₂H₅). The central carbon atom is also bonded to two hydrogen atoms, but these are not explicitly shown in the condensed formula. The compound is named as 2,2-dimethylpropane according to the IUPAC nomenclature system.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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