How can I explain the bromination of alkanes?
It happens according to radical halogenation. The key steps are shown below.
Note that each key step may happen more than once, in such a way that all reagents are used up and the reaction stops. Just because it is written X number of times does not mean it happens X number of times.
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The bromination of alkanes involves the substitution of a hydrogen atom in an alkane molecule with a bromine atom. This reaction typically occurs in the presence of a halogen carrier such as iron or aluminum bromide, which helps initiate the reaction by forming a complex with the bromine molecule. The reaction proceeds via a free radical mechanism, where the alkane molecule undergoes homolytic cleavage of the carbon-hydrogen bond to generate a methyl radical. This methyl radical then reacts with a bromine molecule to form a bromomethane molecule and a bromine radical. The bromine radical can then react with another alkane molecule, continuing the chain reaction until all available hydrogen atoms have been replaced by bromine atoms.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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