How can I draw the structures of 4 isomers of amides for the formula #C_5H_11NO# ?
There are at many isomeric amides with formula C₅H₁₁NO. Here's how to draw the unsubstituted amides.
If the amide is unsubstituted, it must contain a CONH₂ group. The rest of the molecule must be C₄H₉.
So you draw all possible chains containing 4 carbon atoms. Then you add the CONH₂ group to every possible location on these chains.
4 C in a Row
You can put the amide group on C-1 or C-2. This gives pentanamide
and 2-methylbutanamide.
3 C in a Row
This gives us a 2-methylpropane chain. You can put the amide group on C-1 or C-2.
This gives 3-methylbutanamide
and 2,2-dimethylpropanamide.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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