How can I draw the following ethers: 1-propoxypentane, 2-ethoxybutane, 1-methoxy-4-chlorohexane, and 3-butoxy-2,4-dimethyloctane?

Question

Nolan Allen · Accepted Answer

You draw the main chain. Then you attach the alkoxy group to the appropriate carbon atom.

1-Propoxypentane

Pentane is a chain of 5 carbon atoms.

The propoxy group is a 3-carbon chain with an #"O"# atom at #"C-1"#.

Draw a chain of five carbon atoms and attach the 1-propoxy group to #"C-1"# of the chain.

2-Ethoxybutane

Attach an ethoxy group to #"C-2"# of a butane chain.

4-Chloro-1-methoxyhexane

Draw a 6-carbon chain. Attach a methoxy group to #"C-1"# and a #"Cl"# atom to #"C-4"#.

3-Butoxy-2,4-dimethyloctane

Draw an 8-carbon chain. Attach a butoxy group to #"C-3"# and methyl groups to #"C-2"# and #"C-4"#.

Zoe Alexander · Answer

undefined To draw the following ethers:

1. 1-propoxypentane: Draw a five-carbon chain with an oxygen atom attached to the first carbon.
2. 2-ethoxybutane: Draw a four-carbon chain with an oxygen atom attached to the second carbon.
3. 1-methoxy-4-chlorohexane: Draw a six-carbon chain with an oxygen atom attached to the first carbon and a chlorine atom attached to the fourth carbon.
4. 3-butoxy-2,4-dimethyloctane: Draw an eight-carbon chain with an oxygen atom attached to the third carbon, a methyl group attached to the second and fourth carbons, and a butyl group attached to the third carbon.