How can I draw a chiral isomer of 1,2-dibromocyclobutane?
See explanation.
Here is how it would be:
Of course cyclobutane is not a square, but we draw it like this for easier representation.
Unless you have to label the molecule R and S, you can place the Bromine atoms pointing forward or backward as you wish.
I here chose to point one forward and one backward.
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To draw a chiral isomer of 1,2-dibromocyclobutane, you need to place the bromine atoms on opposite sides of the cyclobutane ring. This results in a molecule with two different arrangements of atoms around the chiral center, making it chiral.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What stereochemistry results from the addition of one equiv of bromine to the #"1-methylcyclohexene"#?

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