How can I complete the following equation: #CH_3CH_2NH-CH_3 + HBr ->?#
This must be understood to be an acid-base neutralization reaction.
Strong acid HBr is.
An amine is CH₃CH₂NHCH₃. Because of the lone pair electrons on the N atom, amines are bases.
The basic amine will receive a proton from the acidic HBr, leaving behind a Br⁻ ion, in accordance with the Brønsted-Lowry theory.
After accepting the H⁺, the amine will change into [CH₃CH₂NH₂CH₃]⁺.
Thus, CH₃CH₂NHCH₃ + HBr → [CH₃CH₂NH₂CH₃]⁺ Br⁻ is the equation.
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CH3CH2NH-CH3 + HBr -> CH3CH2NH2+ + Br-
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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