How can I calculate the percent composition of CFBrO?

Question

Olivia Anton · Accepted Answer

The molar masses of the compound itself and each individual atom that makes up the compound can be used to calculate the percent composition. In your case, the molar masses of the atoms that make up the compound #"CFBrO"# are #"C": "12.011 g/mol"#
#"F": "18.9984 g/mol"#
#"Br": "79.904 g/mol"#
#"O": "15.9994 g/mol"# The compound's molar mass is equal to the total of the molar masses of the constituent atoms. #"CFBrO": 12.011 + 18.9984 + 79.904 + 15.9994 = "126.9074 g/mol"# Now, divide the molar mass of each element by the compound's molar mass, and multiply the result by 100 to find the percent composition of the compound. This will give you the contribution of each element to the mass of the compound. #"C": "12.011"/"126.9074" * 100 = "9.47%"# #"F": "18.9984"/"126.9074" * 100 = "14.97%"# #"Br": 79.904/126.9074 * 100= "62.96%"# #"O": 15.994/126.9074 * 100 = "12.60%"# This means that, for every 100 g of #"CFBrO"#, you get #"9.47 g"# #-># carbon;
#"14.97 g"# #-># fluorine;
#"62.96 g"# #-># bromine;
#"12.6 g"# #-># oxygen;

Luna Chen · Answer

undefined To calculate the percent composition of CFBrO, you need to determine the molar mass of each element in the compound and then divide the individual molar masses by the molar mass of the entire compound.

Here's the calculation:

1. Find the molar mass of each element:
   - Carbon (C): 12.01 g/mol
   - Fluorine (F): 18.99 g/mol
   - Bromine (Br): 79.90 g/mol
   - Oxygen (O): 16.00 g/mol

2. Calculate the total molar mass of CFBrO:
   Total molar mass = (1 * molar mass of C) + (1 * molar mass of F) + (1 * molar mass of Br) + (1 * molar mass of O)

3. Add the molar masses:
   Total molar mass = (1 * 12.01 g/mol) + (1 * 18.99 g/mol) + (1 * 79.90 g/mol) + (1 * 16.00 g/mol)

4. Calculate the total molar mass:
   Total molar mass = 12.01 + 18.99 + 79.90 + 16.00 = 126.90 g/mol

5. Calculate the pe