How can I calculate solubility of calcium hydroxide?

Question

Serenity Allen · Accepted Answer

A sparingly soluble electrolyte such as calcium hydroxide can have its solubility determined using the solubility product constant. This query is comparable to that at How can I determine the molar solubility of baso4 given a ksp of 1-07-10-10?https://tutor.hix.ai For Ca(OH)₂, the solubility product constant is 5.5 × 10⁻⁶. The chemical equation that is in balance is Ca(OH)₂(s) ⇌ Ca²⁺(aq) + 2OH⁻(aq)
I/mol·L⁻¹: -; 0; 0
C/mol·L⁻¹: -; +#x#; +#2x#
E/mol·L⁻¹: -; #x#; #2x# #K_"sp"# = [Ca²⁺][ OH⁻]² = #x × (2x)^2 = 4x^3# = 5.5 × 10⁻⁶ #x^3# = 1.375 × 10⁻⁶ (2 significant figures + 2 guard digits) #x# = ∛(1.375 ×10⁻⁶) = 1.1 × 10⁻² Solubility = #x# mol/L = 1.1 × 10⁻² mol/L = 0.011 mol/L

Kai Bowman · Answer

undefined The solubility of calcium hydroxide (Ca(OH)2) can be calculated using its Ksp value, which is the equilibrium constant for the dissolution of the compound in water. The Ksp expression for calcium hydroxide is:

Ksp = [Ca2+][OH-]^2

The solubility (S) of calcium hydroxide can be determined by assuming that x mol/L of Ca(OH)2 dissociates into Ca2+ and 2x mol/L of OH- ions, where x is the solubility of Ca(OH)2. Substituting these values into the Ksp expression and solving for x will give you the solubility of calcium hydroxide.