How can Gay-Lussac's law can be derived from the combined gas law?

Answer 1
If memory serves, that is the #P/T# relation, which is at constant volume and mols of gas.

We could start from the "combined gas law", but it came from the ideal gas law, so it would be simpler to start from the ideal gas law:

#PV = nRT#
Define the initial and final states, with constant #V# and #n# (#V_1 = V_2 -= V#, #n_1 = n_2 -= n#):
#P_1V = nRT_1# #" "bb((1))#
#P_2V = nRT_2# #" "bb((2))#

By division,

#((2))/((1)) = (P_2cancel(V))/(P_1cancel(V)) = (cancel(nR)T_2)/(cancel(nR)T_1)#

Therefore,

#P_2/P_1 = T_2/T_1#

or

#color(blue)(P_2/T_2 = P_1/T_1)#

which is Gay-Lussac's Law.

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Answer 2

Gay-Lussac's Law can be derived from the Combined Gas Law by keeping the quantity of gas and the amount of moles constant. The equation for Gay-Lussac's Law is obtained by isolating the variables associated with temperature in the Combined Gas Law equation. The resulting expression is P₁/T₁ = P₂/T₂, where P is pressure and T is temperature.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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