How are mole ratios derived from balance equations?

Answer 1

From the stoichiometric coefficients of the given equation.

So you have the got the equation, and mass and charge are balanced, as they must be if the reaction reflects physical reality:

#CH_4(g) + 2O_2(g) rarr CO_2(g) +2H_2O(g) + Delta#
The mole ration simply follows the ratio of the stoichiometric coefficients: #1:2:1:2#, i.e. #16*g# methane is oxidized by #64*g# of dioxygen to #44*g# of carbon, and #36*g# of water. Mass and charge are balanced.....................

And see this old question.

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Answer 2

Mole ratios are derived from balanced chemical equations by comparing the coefficients of reactants and products.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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