Home > Trigonometry > Solving Right Triangles

Help please? #costheta -tanthetacostheta =0#

Answer 1

Abigail Armstrong

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Answer 2

Grace Ashcraft

#x=pi/4+pin#

#cosx-tanxcosx=0#

Factor:

#cosx(1-tanx)=0#

#:.#

#cos(x)=0#

#x=arccos(cosx)=arccos(0)=>x=pi/2+2pin,(3pi)/2+2pin#

#tanx# is undefined for these values.

#1-tanx=0#

#tanx=1#

#x=arctan(tanx)=arctan(1)=>x=pi/4+pin#

For integers #n#

The equation is not satisfied by any of the options.

Somewhere must be a mistake.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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