# Help me to solve this question please?

I got

First of all, I assume we are just solving for

For

#a(-1) + b = 1#

If we repeat the same process, we get the second equation.

#a(2) + b = 4#

If we solve by substitution, we get

#2a + 1 + a = 4#

#3a = 3#

#a = 1#

It follows that

We confirm graphically

As you can see, the graph is continuous on all

Hopefully this helps!

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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