Gold is a very unreactive element. It only bonds with strong chemicals. As Gold has a single outer S shell electron it should be reactive. Why isn't it?

Answer 1

The electron configuration of gold is:

#[Xe] 4f^14 5d^10 6s^1#
Gold is also the go-to element when thinking about relativistic effects. Its #6s# electron moves very quickly. Gold's #1s# electron moves at around #57.7%# the speed of light, so the #6s# electron, probably quite fast.
This high speed #6s# electron is then more attracted to the nucleus than we expect, and the #6s# orbital contracts (relative to without relativistic effects). To maintain orthogonality of all orbitals, the core #5d# and #4f# orbitals expand.
Thus, the #6s# electron becomes less accessible for bonding than we expect and fairly dissimilar in energy to many incoming reactants, to such an extent that gold is mostly unreactive.

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Answer 2

Gold's single outer S shell electron is tightly bound, requiring substantial energy for reaction. The inertness is due to its stable electronic configuration and reluctance to lose or gain electrons.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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