Given x(t)=3sin(t) - 3, y(t)=t-1 for 0 is less than or equal to t is less than or equal to 2pi How do you find the position of the particle at t=3?

Answer 1

#(-2.6, 2.0)#

We have x and y parameterised in terms of t. We simply sub #t=3# into these expressions for x and y to obtain the position:
#x(3) = 3sin(3) - 3 = -2.577#
#y(3) = 3-1 = 2#
Position is #(-2.6, 2.0)#
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Answer 2

To find the position of the particle at ( t = 3 ), we substitute ( t = 3 ) into the parametric equations for ( x(t) ) and ( y(t) ):

[ x(3) = 3\sin(3) - 3 ] [ y(3) = 3 - 1 ]

After calculating these values, we obtain the coordinates of the particle at ( t = 3 ), which represent its position at that time.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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