# Given #(x^2-9)/(x-3)# how do you find the limit as x approaches 3?

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To find the limit as x approaches 3 for the expression (x^2-9)/(x-3), we can simplify the expression by factoring the numerator. The numerator can be factored as (x-3)(x+3). Canceling out the common factor of (x-3) in the numerator and denominator, we are left with (x+3). Now, substituting x=3 into the simplified expression, we get (3+3) = 6. Therefore, the limit as x approaches 3 for the given expression is 6.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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