# Given the specific heat of lead is 0.129 J/g#*#K and that it takes 93.4 J of energy to heat a sample of lead from 22.3°C to 40.°C, how do you find the mass of the lead.?

The equation you want is

In the question, we want to find mass, so we rearrange to make mass the subject:

Now we have

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You can find the mass of the lead using the formula:

mass = heat energy / (specific heat * change in temperature)

Substitute the given values:

mass = 93.4 J / (0.129 J/g*K * (40.0°C - 22.3°C))

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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